# LeetCode Next Permutation

LeetCode Next Permutation

Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers.

If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order).

The replacement must be in-place, do not allocate extra memory.

Here are some examples. Inputs are in the left-hand column and its corresponding outputs are in the right-hand column.
`1,2,3``1,3,2`
`3,2,1``1,2,3`
`1,1,5``1,5,1`

```class Solution {
public:
void nextPermutation(vector<int>& nums) { // 4876543
for (int i = nums.size() - 1; i > 0; i--) {
if (nums[i] > nums[i - 1]) { // 8 > 4
int min_idx = i, min_val = INT_MAX;
for (int j = nums.size() - 1; j > i; j--) {
if (nums[j] > nums[i - 1] && nums[j] < min_val) { // 5 > 4
min_idx = j;
min_val = nums[j];
}
}
swap(nums[i - 1], nums[min_idx]); // 5876443
reverse(nums.begin() + i, nums.end()); // 5344678
return;
}
}
reverse(nums.begin(), nums.end());
}
};
```