LeetCode Display Table of Food Orders in a Restaurant

1418. Display Table of Food Orders in a Restaurant

Given the array orders, which represents the orders that customers have done in a restaurant. More specifically orders[i]=[customerNamei,tableNumberi,foodItemi] where customerNamei is the name of the customer, tableNumberi is the table customer sit at, and foodItemi is the item customer orders.

Return the restaurant’s “display table. The “display table” is a table whose row entries denote how many of each food item each table ordered. The first column is the table number and the remaining columns correspond to each food item in alphabetical order. The first row should be a header whose first column is “Table”, followed by the names of the food items. Note that the customer names are not part of the table. Additionally, the rows should be sorted in numerically increasing order.

Example 1:

Input: orders = [["David","3","Ceviche"],["Corina","10","Beef Burrito"],["David","3","Fried Chicken"],["Carla","5","Water"],["Carla","5","Ceviche"],["Rous","3","Ceviche"]]
Output: [["Table","Beef Burrito","Ceviche","Fried Chicken","Water"],["3","0","2","1","0"],["5","0","1","0","1"],["10","1","0","0","0"]] 
Explanation:
The displaying table looks like:
Table,Beef Burrito,Ceviche,Fried Chicken,Water
3    ,0           ,2      ,1            ,0
5    ,0           ,1      ,0            ,1
10   ,1           ,0      ,0            ,0
For the table 3: David orders "Ceviche" and "Fried Chicken", and Rous orders "Ceviche".
For the table 5: Carla orders "Water" and "Ceviche".
For the table 10: Corina orders "Beef Burrito". 

Example 2:

Input: orders = [["James","12","Fried Chicken"],["Ratesh","12","Fried Chicken"],["Amadeus","12","Fried Chicken"],["Adam","1","Canadian Waffles"],["Brianna","1","Canadian Waffles"]]
Output: [["Table","Canadian Waffles","Fried Chicken"],["1","2","0"],["12","0","3"]] 
Explanation: 
For the table 1: Adam and Brianna order "Canadian Waffles".
For the table 12: James, Ratesh and Amadeus order "Fried Chicken".

Example 3:

Input: orders = [["Laura","2","Bean Burrito"],["Jhon","2","Beef Burrito"],["Melissa","2","Soda"]]
Output: [["Table","Bean Burrito","Beef Burrito","Soda"],["2","1","1","1"]]

Constraints:

  • 1 <= orders.length <= 5 * 10^4
  • orders[i].length == 3
  • 1 <= customerNamei.length, foodItemi.length <= 20
  • customerNamei and foodItemi consist of lowercase and uppercase English letters and the space character.
  • tableNumberi is a valid integer between 1 and 500.

很啰嗦的一个题目。给定一系列顾客的点餐清单,输出整个餐厅的点餐信息表。直接按照题意做就行,题目要求行按桌号升序排列,列按菜名字母序排列,所以行可以用vector下标存储,菜名放到set里会自动有序排列。

完整代码如下:

class Solution {
public:
	vector<vector<string>> displayTable(vector<vector<string>>& orders) {
		vector<map<string, int>> tables(501, map<string, int>());
		set<string> allfoods;
		for (int i = 0; i < orders.size(); ++i) {
			string name = orders[i][0], tb = orders[i][1], food = orders[i][2];
			int ntb = stoi(tb.c_str());
			++tables[ntb][food];
			allfoods.insert(food);
		}
		vector<vector<string>> ans;
		vector<string> header;
		header.push_back("Table");
		for (set<string>::iterator it = allfoods.begin(); it != allfoods.end(); ++it)header.push_back(*it);
		ans.push_back(header);
		for (int i = 1; i <= 500; ++i) {
			vector<string> cur;
			if (tables[i].size() > 0) {
				cur.push_back(to_string(i));
				for (set<string>::iterator it = allfoods.begin(); it != allfoods.end(); ++it) {
					cur.push_back(to_string(tables[i][*it]));
				}
				ans.push_back(cur);
			}
		}
		return ans;
	}
};

本代码提交AC,用时1152MS。

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