Given numBottles
full water bottles, you can exchange numExchange
empty water bottles for one full water bottle.
The operation of drinking a full water bottle turns it into an empty bottle.
Return the maximum number of water bottles you can drink.
Example 1:
Input: numBottles = 9, numExchange = 3 Output: 13 Explanation: You can exchange 3 empty bottles to get 1 full water bottle. Number of water bottles you can drink: 9 + 3 + 1 = 13.
Example 2:
Input: numBottles = 15, numExchange = 4 Output: 19 Explanation: You can exchange 4 empty bottles to get 1 full water bottle. Number of water bottles you can drink: 15 + 3 + 1 = 19.
Example 3:
Input: numBottles = 5, numExchange = 5 Output: 6
Example 4:
Input: numBottles = 2, numExchange = 3 Output: 2
Constraints:
1 <= numBottles <= 100
2 <= numExchange <= 100
很贴近生活的一个题。初始有n瓶满饮料,喝完之后,可以每m个空瓶子换一瓶新饮料,问最终能喝多少瓶饮料。
直接模拟,代码如下:
class Solution {
public:
int numWaterBottles(int numBottles, int numExchange) {
int full = numBottles, empty = 0, div = numExchange;
int ans = 0;
while (full + empty >= div) {
ans += full;
empty += full;
full = empty / div;
empty = empty % div;
}
return ans + full;
}
};
本代码提交AC。