Given a string s
and an integer array indices
of the same length.
The string s
will be shuffled such that the character at the ith
position moves to indices[i]
in the shuffled string.
Return the shuffled string.
Example 1:
Input: s = "codeleet", indices
= [4,5,6,7,0,2,1,3]
Output: "leetcode"
Explanation: As shown, "codeleet" becomes "leetcode" after shuffling.
Example 2:
Input: s = "abc", indices
= [0,1,2]
Output: "abc"
Explanation: After shuffling, each character remains in its position.
Example 3:
Input: s = "aiohn", indices
= [3,1,4,2,0]
Output: "nihao"
Example 4:
Input: s = "aaiougrt", indices
= [4,0,2,6,7,3,1,5]
Output: "arigatou"
Example 5:
Input: s = "art", indices
= [1,0,2]
Output: "rat"
Constraints:
s.length == indices.length == n
1 <= n <= 100
s
contains only lower-case English letters.0 <= indices[i] < n
- All values of
indices
are unique (i.e.indices
is a permutation of the integers from0
ton - 1
).
给定一个字符串,根据给定规则进行shuffle,直接照做。代码如下:
class Solution {
public:
string restoreString(string s, vector<int>& indices) {
int n = s.size();
string ans = s;
for (int i = 0; i < n; ++i)ans[indices[i]] = s[i];
return ans;
}
};
本代码提交AC。